Java How to find a target element within a search pool using binary search?

To find a target element within a search pool using binary search in Java, you can use a recursive or iterative algorithm to divide the search pool into smaller sections and search for the target element in each section.

Here's an example of how to find a target element within a search pool using binary search in Java:

public static int binarySearch(int[] array, int target, int start, int end) {
  if (start > end) {
    return -1;
  }

  int mid = (start + end) / 2;

  if (array[mid] == target) {
    return mid;
  } else if (array[mid] < target) {
    return binarySearch(array, target, mid + 1, end);
  } else {
    return binarySearch(array, target, start, mid - 1);
  }
}

// Test the binary search function
int[] array = {1, 2, 3, 4, 5};
int target = 3;

int index = binarySearch(array, target, 0, array.length - 1);

if (index != -1) {
  System.out.println("Found target at index " + index);
} else {
  System.out.println("Target not found");
}

In the above example, the binarySearch() method uses a recursive approach to divide the search pool into smaller sections and search for the target element in each section. The method takes four arguments: the array to search, the target element to find, the start index of the search pool, and the end index of the search pool.

The method first checks if the start index is greater than the end index. If this is the case, it means that the target element was not found and the method returns -1.

If the start index is not greater than the end index, the method calculates the middle index of the search pool using the start and end indices. It then checks if the element at the middle index is equal to the target element. If it is, the method returns the middle index.

If the element at the middle index is not equal to the target element, the method checks if the element is greater than or less than the target element.