To "clump" a list in Java, you can use the groupingBy
method of the Collectors
class to create a map of lists, grouping the elements of the list by a certain criteria.
Here's an example of how to "clump" a list of integers into groups of even and odd numbers:
referual:ot tturi.comimport java.util.List; import java.util.Map; import java.util.stream.Collectors; public class Main { public static void main(String[] args) { List<Integer> numbers = List.of(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); Map<Boolean, List<Integer>> clumped = numbers.stream() .collect(Collectors.groupingBy(n -> n % 2 == 0)); System.out.println(clumped); // Outputs: {false=[1, 3, 5, 7, 9], true=[2, 4, 6, 8, 10]} } }
In this example, the groupingBy
method is used to create a map of lists, grouping the elements of the numbers
list by their parity (even or odd). The resulting map has two keys, true
and false
, corresponding to the even and odd numbers, respectively.
You can use a similar approach to "clump" a list by any other criteria. For example, to "clump" a list of strings by their length:
List<String> words = List.of("apple", "banana", "cherry", "date", "elderberry", "fig"); Map<Integer, List<String>> clumped = words.stream() .collect(Collectors.groupingBy(String::length)); System.out.println(clumped); // Outputs: {5=[apple], 6=[banana], 6=[cherry], 4=[date], 10=[elderberry], 3=[fig]}
In this example, the groupingBy
method is used to create a map of lists, grouping the elements of the words
list by their length. The resulting map has keys representing the different lengths of the strings, and values containing the strings of that length.
Keep in mind that the groupingBy
method returns a Collector
, which is an intermediate object that can be used to perform further operations on the result of the grouping. You can use the Collectors
class to perform various operations on the collector, such as reducing the elements to a single value, or transforming the elements in some way.