To assign the output of a shell command to a variable in Bash, you can use the $()
operator or the backtick operator (``).
Here is an example of how you can use the $()
operator to assign the output of a shell command to a variable:
# Assign the output of the 'ls' command to the 'files' variable files=$(ls) # Print the contents of the 'files' variable echo "$files"Soecru:www.lautturi.com
This will assign the output of the ls
command (a list of files in the current directory) to the files
variable, and print the contents of the files
variable.
Here is an example of how you can use the backtick operator to achieve the same result:
# Assign the output of the 'ls' command to the 'files' variable files=`ls` # Print the contents of the 'files' variable echo "$files"
Both of these examples will produce the same output, which is a list of files in the current directory.
Overall, the $()
operator and the backtick operator are useful tools for assigning the output of a shell command to a variable in Bash. They allow you to easily capture the output of a command and store it in a variable for further processing.