how to get the size of an array in c language

There are two methods to get the size of an array in C language.

1. Use sizeof to obtain the occupied memory size and calculate the array size.
2. Use strlen, which is applicable to arrays of char character type.

/*
Get the array size in C language
*/

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <string.h>

// traverse using pointer
void displayArr1(int * array, int size,int tsize) {
    printf("%d ",size);
    printf("%d ", tsize);
	for(int i = 0; i < size; i++) {
		*array += tsize;
		printf("%d ", *(array++));
	}
	printf("\n");
}

// traverse normally
void displayArr2(int array[], int size,int tsize) {
//	int size = sizeof(array) / sizeof(int)；//The array size cannot be obtained correctly in a subfunction
	for(int i = 0; i < size; i++) {
		array[i] += tsize;
		printf("%d ", array[i]);
	}
	printf("\n");
}

int main(int argc, char *argv[]) {
	int arr[] = {1,2,3,45,67};
//	displayArr1(arr, sizeof(arr) /sizeof(arr[0]) , sizeof(arr[0]));
	displayArr1(arr, sizeof(arr)/sizeof(int) , sizeof(int));
    return 0;
}

Example of getting array size using strlen:

/*
Get the array size in C language
*/

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <string.h>

void displayArr(char array[], int size) {
	for(int i = 0; i < size; i++) {
		printf("%c ", array[i]);
	}
	printf("\n");
}

int main(int argc, char *argv[]) {
	char arr[] = {'1','2','a','b','e'};

	int size = strlen(arr);
	displayArr(arr, size);
    return 0;
}